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Find the Values Of K For Which the Roots Are Real and Equal in Each of the Following Equation: X2 - 4kx + K = 0 - Mathematics

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प्रश्न

Find the values of k for which the roots are real and equal in each of the following equation:

x2 - 4kx + k = 0

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उत्तर

The given equation is x2 - 4kx + k = 0

The given equation is in the form of ax2 + bx + c = 0

where a = 1, b = -4k and c = k

Therefore, the discriminant

D = b2 - 4ac

= (-4k)2 - 4 x (1) x (k)

= 16k2 - 4k

∵ Roots of the given equation are real and equal

∴ D = 0

⇒ 16k2 - 4k = 0

⇒ 4k(4k - 1) = 0

⇒ 4k = 0

⇒ k = 0

Or

⇒ 4k - 1 = 0

⇒ 4k = 1

⇒ k = 1/4

Hence, the value of k = 0, 1/4

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पाठ 4: Quadratic Equations - Exercise 4.6 [पृष्ठ ४२]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 4 Quadratic Equations
Exercise 4.6 | Q 5.3 | पृष्ठ ४२

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