Question

Find three consecutive natural numbers such that the sum of the first and the second is 15 more than the third.

Answer 1

Let the first conscutive number = x,

Second consecutive number = x + 1

and Third consecutive number = x + 2

According to the condition,

x + x + 1 = 15 + x + 2

⇒ 2x + 1 = 17 +x

⇒ 2x -x = 17 – 1

⇒ x= 16

∴ The first consecutive number = 16

Second consecutive number =16+1 = 17

Third consecutive number =16 + 2=18