Question

Find the values of x for which the distance between the point P (2, –3) and Q (x, 5) is 10.

Answer 1

It is given that distance between P (2, –3) and Q (x, 5) is 10.

In general, the distance between `A(x_1, y_1)` and `B(x_2, y_2)` is given by,

`AB^2 = (x_2 - x_1)^2 + (y_2 - y_1)^2`

So,

`10^2 = (x - 2)^2 + (5 + 3)^2`

On further simplification,

`(x - 2)^2 = 36`

`x = 2 +- 6`

= 8, – 4