Question

Find the values of the following polynomials at a = –2 and b = 3:

a³ – 3a²b + 3ab² – b³

Answer 1

Given, a = –2 and b = 3

So, putting a = –2 and b = 3 in the given expressions, we get

a³ – 3a²b + 3ab² – b³ = (–2)³ –3(–2)²(3) + 3(–2)(3)² – (3)³

= – 8 – 36 – 54 – 27

= –125