Question

Find the values of the following polynomials at a = –2 and b = 3:

a² + b² – ab – b² – a²

Answer 1

Given, a = –2 and b = 3

So, putting a = –2 and b = 3 in the given expressions, we get

a² + b² – ab – b² – a² = (–2)² + (3)² –(–2)(3) – (3)² –(–2)²

= 4 + 9 + 6 – 9 – 4

= 6