Advertisements
Advertisements
प्रश्न
Find the value (s) of k for which each of the following quadratic equation has equal roots : kx2 – 4x – 5 = 0
Advertisements
उत्तर
kx2 – 4x – 5 = 0
Here a = k, b = -4, c = 5
∴ D = b2 - 4ac
= (-4)2 - 4 x k x (-5)
= 16 + 20k
∵ Roots are equal.
∴ D = 0
⇒ b2 - 4ac = 0
∴ 16 + 20k = 0
⇒ 20k = -16
⇒ k = `(-16)/(20)`
= `(-4)/(5)`
Hence k = `(-4)/(5)`.
APPEARS IN
संबंधित प्रश्न
Determine the nature of the roots of the following quadratic equation:
(x - 2a)(x - 2b) = 4ab
Find the values of k for which the roots are real and equal in each of the following equation:
(3k+1)x2 + 2(k + 1)x + k = 0
In each of the following determine the; value of k for which the given value is a solution of the equation:
kx2 + 2x - 3 = 0; x = 2
Solve for x: (x2 - 5x)2 - 7(x2 - 5x) + 6 = 0; x ∈ R.
Discuss the nature of the roots of the following quadratic equations : `2sqrt(3)x^2 - 5x + sqrt(3)` = 0
The quadratic equation `2x^2 - sqrt(5)x + 1 = 0` has ______.
If –5 is a root of the quadratic equation 2x2 + px – 15 = 0, then:
If x2 (a2 + b2) + 2x (ac + bd) + c2 +d2 = 0 has no real roots, then:
(x2 + 1)2 – x2 = 0 has ______.
The roots of quadratic equation x2 – 1 = 0 are ______.
