Question

Find the value of x in the given figure.

Answer 1

∠B = 180° – 120°  .....(Sum of the opposite angles of a quadrilateral are supplementary)

∠B = 60°

∠BCA = 90° ...(Angle in a semicircle)

∠BAC + ∠B + ∠BCA = 180°

x + 60° + 90° = 180°

x + 150° = 180°

x = 180° – 150°

= 30°

The value of x = 30°