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प्रश्न
Find the value of x, if a + 1 = 0 and x2 + ax – 6 = 0.
बेरीज
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उत्तर
If a + 1 = 0, then a = –1
Put this value in the given equation x2 + ax – 6 = 0
x2 – x – 6 = 0
⇒ x2 – 3x + 2x – 6 = 0
⇒ x(x – 3) + 2(x – 3) = 0
⇒ (x – 3)(x + 2) = 0
If x – 3 = 0 or x + 2 = 0
Then x = 3 or x = –2
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