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प्रश्न
Find the value of x for which x tan 45° cot 60° = sin 30° cosec 60°.
बेरीज
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उत्तर
Given: x tan 45° cot 60° = sin 30° cosec 60°
tan 45° = 1, `cot 60^circ = 1/(tan 60^circ) = 1/sqrt(3)`.
Left side = `x xx 1 xx (1/sqrt(3)) = x/sqrt(3)`.
`sin 30^circ = 1/2, "cosec" 60^circ = 1/(sin 60^circ) = 2/sqrt(3)`.
Right side = `(1/2) xx (2/sqrt(3)) = 1/sqrt(3)`.
So `x/sqrt(3) = 1/sqrt(3) ⇒ x = 1`.
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पाठ 11: T-Ratios of Some Particular Angles - EXERCISE 11 [पृष्ठ ५७४]
