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प्रश्न
Find the value of the following expression:
`(sin^2 45^circ + cos^2 45^circ)/(tan^2 60^circ)`
बेरीज
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उत्तर
Given: `(sin^2 45^circ + cos^2 45^circ)/(tan^2 60^circ)`
Step-wise calculation:
1. `sin 45^circ = sqrt(2)/2` and `cos 45^circ = sqrt(2)/2`.
2. `sin^2 45^circ + cos^2 45^circ = (sqrt(2)/2)^2 + (sqrt(2)/2)^2`
= `1/2 + 1/2`
= 1
3. `tan 60^circ = sqrt(3)`.
So, `tan^2 60^circ = (sqrt(3))^2 = 3`.
4. Therefore, the expression = `1/3`.
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