मराठी

Find the value of the following expression: cos 90° + cos^2 45° sin 30° tan 45° - Mathematics

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प्रश्न

Find the value of the following expression:

cos 90° + cos2 45° sin 30° tan 45°

बेरीज
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उत्तर

Given: cos 90° + cos2 45° sin 30° tan 45°

Step-wise calculation:

1. cos 90° = 0.

2. cos 45° = `sqrt(2)/2`

So, `cos^2 45^circ = (sqrt(2)/2)^2`

= `1/2`

3. `sin 30^circ = 1/2`.

4. tan 45° = 1.

5. Multiply the factors:

cos2 45° · sin 30° · tan 45° 

= `(1/2) xx (1/2) xx 1`

= `1/4`

6. Add cos 90°:

`0 + 1/4 = 1/4`

The value of the expression is `1/4`.

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पाठ 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [पृष्ठ ३७२]

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नूतन Mathematics [English] Class 9 ICSE
पाठ 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18A | Q 10. | पृष्ठ ३७२
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