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प्रश्न
Find the value of Dx for the equation 4x + 3y = 19 and 4x – 3y = –11.
पर्याय
24
0
–24
108
MCQ
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उत्तर
–24
Explanation:
Here, a1 = 4, b1 = 3, c1 = 19
a2 = 4, b2 = –3, c2 = –11
∴ Dx = `|(c_1, b_1),(c_2, b_2)|`
= `|(19, 3),(-11, -3)|`
= –57 + 33
= –24
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