Question

Find the value of discriminant. 

`sqrt2x^2 + 4x + 2sqrt2 = 0`

Answer 1

`sqrt2x^2 + 4x + 2sqrt2 = 0`

Comparing the given equation with ax² + bx + c = 0, we get,

`a = sqrt2, b = 4, c = 2sqrt2`

So, the discriminant (D),

`∴ b^2 − 4ac = (4)^2 − 4 × (sqrt2) × (2sqrt2)`

`∴ b^2 − 4ac = 16 − 16`

`∴ b^2 − 4ac = 0`.