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प्रश्न
Find the value of a and b in the following:
`(3sqrt(5) + 1)/(2sqrt(5) + 4) = a + bsqrt(5)`
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उत्तर
We are given:
`(3sqrt(5) + 1)/(2sqrt(5) + 4) = a + bsqrt(5)`
Step 1: Multiply numerator and denominator by the conjugate of the denominator:
Conjugate of `2sqrt(5) + 4` is `2sqrt(5) - 4`
`(3sqrt(5) + 1)/(2sqrt(5) + 4) xx (2sqrt(5) - 4)/(2sqrt(5) - 4)`
Step 2: Expand numerator using distributive law:
`(3sqrt(5) + 1)(2sqrt(5) - 4)`
= `3sqrt(5) xx 2sqrt(5) + 3sqrt(5) xx (-4) + 1 xx 2sqrt(5) + 1 xx (-4) `
= `6 xx 5 - 12sqrt(5) + 2sqrt(5) - 4`
= `30 - 10sqrt(5) - 4`
= `26 - 10sqrt(5)`
Step 3: Simplify denominator using (a + b)(a – b) = a2 – b2:
`(2sqrt(5))^2 - 4^2`
= 4 × 5 – 16
= 20 – 16
= 4
Step 4: Final expression:
`(26 - 10sqrt(5))/4`
= `26/4 - 10/4 sqrt(5)`
= `13/2 - 5/2 sqrt(5)`
`a = 13/2, b = -5/2`
