मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the value of (1.01)5, correct up to three places of decimals.

Advertisements
Advertisements

प्रश्न

Find the value of (1.01)5, correct up to three places of decimals.

बेरीज
Advertisements

उत्तर

(1.01)5 = (1 + 0.01)5

= 5C0(1)5 + 5C1(1)4(0.01) + 5C2(1)3(0.01)2 + 5C3(1)2(0.01)3 + 5C4(1)(0.01)4 + 5C5(0.01)5

Now, 5C0 = 1 = 5C5

5C1 = 5 = 5C4

5C2 = `(5 xx 4)/(1 xx 2)` = 10 = 5C3

∴ (1.01)5 = 1 × 1 + 5 × 1 × 0.01 + 10 × 1 × 0.0001 + 10 × 1 × 0.000001 + ...

= 1 + 0.05 + 0.001 + 0.00001 + ...

= 1.05101...

= 1.051, correct up to three places of decimals.

shaalaa.com
Binomial Theorem for Positive Integral Index
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Methods of Induction and Binomial Theorem - Exercise 4.2 [पृष्ठ ७७]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 4 Methods of Induction and Binomial Theorem
Exercise 4.2 | Q 9 | पृष्ठ ७७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×