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Find the unit vector parallel to abC3a→-2b→+4C→ if aijkbijka→=3i^-j^-4k^,b→=-2i^+4j^-3k^, and cijkc→=i^+2j^-k^ - Mathematics

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प्रश्न

Find the unit vector parallel to `3vec"a" - 2vec"b" + 4vec"C"` if `vec"a" = 3hat"i" - hat"j" - 4hat"k", vec"b" = -2hat"i" + 4hat"j" - 3hat"k"`, and `vec"c" = hat"i" + 2hat"j" - hat"k"`

बेरीज
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उत्तर

Given that `vec"a" = 3hat"i" - hat"j" - 4hat"k"`

`vec"b" = -2hat"i" + 4hat"j" - 3hat"k"`

`vec"c" = hat"i" + 2hat"j" - hat"k"`

`3vec"a" - 2vec"b" + 4vec"c" = 3(3hat"i" - hat"j" - 4hat"k") -2(-2hat"i" + 4hat"j" - 3hat"k") + 4(hat"i" + 2hat"j" - hat"k")`

= `9hat"i" - 3hat"j" - 12hat"k" + 4hat"i" - 8hat"j" + 6hat"k" + 4hat"i" + 8hat"j" - 4hat"k"`

`3vec"a" - 2vec"b" + 4vec"c" = 17hat"i" - 3hat"j" - 10hat"k"`

The unit vector parallel to `3vec"a" - 2vec"b" + 4vec"c"` is

= `(3vec"a" - 2vec"b" + 4vec"c")/|3vec"a" - 2vec"b" + 4vec"c"|`

= `(17hat"i" - 3hat"j" - 10hat"k")/|17hat"i" - 3hat"j" - 10hat"k"|`

= `(17hat"i" - 3hat"j" - 10hat"k")/sqrt(17^2 + (-3)^2 + 10)^2`

= `(17hat"i" - 3hat"j" - 10hat"k")/sqrt(289 + 9 + 100)`

=  `(17hat"i" - 3hat"j" - 10hat"k")/sqrt(398)`

Thus, the unut vector parallel to `3vec"a" - 2vec"b" + 4vec"c"` is

=  `(17hat"i" - 3hat"j" - 10hat"k")/sqrt(398)`

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पाठ 8: Vector Algebra - Exercise 8.2 [पृष्ठ ६८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 8 Vector Algebra
Exercise 8.2 | Q 13 | पृष्ठ ६८
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