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प्रश्न
Find the sum of 7 terms of the series 2 + 0.2 + 0.02 + ....
बेरीज
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उत्तर
a = 2
r = `0.2/2`
= 0.1 < 1
`S_n = (a(1 - r^n))/(1 - r)`
`S_7 = (2(1 - (0.1)^7))/(1 - (0.1))`
`S_7 = (2(1 - 0.1^7))/(0.9)`
= `(2 xx 10)/9(1 - (1/10)^7)`
= `20/9(1 - (1/10)^7)`
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