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प्रश्न
Find the square of `3"x"+2/"y"`
बेरीज
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उत्तर
`3"x"+2/"y"`
`(3"x"+2/"y")^2=(3"x")^2+(2/"y")^2+2(3"x")(2/"y")`
`=9"x"^2+4/"y"^2+"12x"/"y"`
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संबंधित प्रश्न
Expand: `("a"+1/(2"a"))^2`
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If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
