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प्रश्न
Find the square of `3"x"+2/"y"`
बेरीज
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उत्तर
`3"x"+2/"y"`
`(3"x"+2/"y")^2=(3"x")^2+(2/"y")^2+2(3"x")(2/"y")`
`=9"x"^2+4/"y"^2+"12x"/"y"`
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संबंधित प्रश्न
Expand: `("a"+1/(2"a"))^2`
Expand : `(2"a"-1/"a")^2`
Expand : (a+b−c)2
Expand : `(3"x"+1/(3"x"))^2`
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If `"a" +1/"a"=2`, find: `"a"^4+1/"a"^4`
If `2"a"+1/(2"a")=8`, find : `16"a"^4+1/(16"a"^4)`
If `3"x"-1/(3"x")=5`, find : `81"x"^4+1/(81"x"^4)`
Expand : (3x – 4y + 5z)2
Expand : (2a – 5b – 4c)2
