Advertisements
Advertisements
प्रश्न
Find the smallest number which when divided by 8, 9, 10, 15, or 20 gives a remainder of 5 every time.
Advertisements
उत्तर
LCM of 8, 9, 10, 15, and 20 are given by
| 2 | 8, 9, 10, 15, 20 |
| 2 | 4, 9, 5, 15, 10 |
| 5 | 2, 9, 5, 15, 5 |
| 3 | 2, 9, 1, 3, 1 |
| 2, 3, 1, 1, 1 |
LCM = 2 × 2 × 5 × 3 × 2 × 3
= 20 × 6 × 3
= 120 × 3
= 360
The smallest number = 360 + 5 = 365
Hence, 365 is the smallest number which when divided by 8, 9, 10, 15, and 20 gives a remainder of 5 every time.
संबंधित प्रश्न
Find out the LCM of the following number:
8, 11
Find the LCM:
10, 15, 20
Find the HCF and LCM of the numbers given below. Verify that their product is equal to the product of the given numbers.
15, 60
Which two consecutive even numbers have an LCM of 180?
The product of two numbers is 2160 and their HCF is 12. Find their LCM.
An electronic device makes a beep every 15 minutes. Another device makes a beep after every 20 minutes. They beeped together at 6 a.m. At what time will they next beep together?
Find the least 5-digit number which is exactly divisible by 20, 25, 30.
On dividing a certain number by 8, 10, 12, 14 the remainder is always 3. Which is the smallest such number?
The LCM of two successive numbers is the product of the numbers
Wilson, Mathan and Guna can complete one round of a circular track in 10, 15 and 20 minutes respectively. If they start together at 7 a.m from the starting point, at what time will they meet together again at the starting point?
