Question

Find the slope of the diagonals of a quadrilateral with vertices A(1, 7), B(6, 3), C(0, –3) and D(–3, 3).

Answer 1

Suppose ABCD is the given quadrilateral.

\[\therefore\text{Slope of line AC}=\frac{y_2-y_1}{x_2-x_1}\]

Slope of AC = \[\frac{7 + 3}{1 - 0} = \frac{10}{1} = 10\]

\[\therefore\text{Slope of line BD}=\frac{y_2-y_1}{x_2-x_1}\]
Slope of BD = \[\frac{3 - 3}{6 + 3} = 0\]

∴ The slopes of the diagonals of the quadrilateral are 10 and 0.