Question

Find the ratio in which the line segment joining the points A(3, –3) and B(–2, 7) is divided by x-axis. Also, find the point of division.

Answer 1

The line segment joining the points A(3, -3) and B(-2,7)  is divided by x-axis. Let the required ratio be k : 1 So ,

` 0= (k (7) -3)/(k+1) ⇒ k =3/7`

Now, 

`"Point of division" = ((k(-2)+3)/(k+1 \) , (k(7)-3)/(k+1))`

`=((3/7 xx(-2)+3)/(3/7+1) , (3/7xx (7) -3)/(3/7 +1))    (∵ k = 3/7)`

`= ((-6+21)/(3+7), (21-21)/(3+7))`

`=(3/2,0)`

`"Hence, the required ratio is 3:7and the point of division is"(3/2, 0)`