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प्रश्न
Find the ratio in which the line segment joining the following points is divided by the X-axis:
(5, 4), (1, −3)
बेरीज
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उत्तर
If a point P divides the line joining A(x1, y1) and B(x2, y2) in the ratio k : 1 (AP : PB = k : 1),
Then, P = `((kx_2 + x_1) / (k + 1)), ((ky_2 + y_1) / (k + 1))`
Let the x-axis cut AB at P and let AP : PB = k : 1.
Then P has coordinates:
P = `(((k xx 1) + 5)/(k + 1)), (((k xx (−3)) + 4)/(k + 1))`
Because P lies on the x-axis, its y-coordinate is 0.
So set the y-coordinate equal to 0:
`(k(−3) + 4) / (k + 1) = 0`
−3k + 4 = 0
∴ k = `4 / 3`
Convert k : 1 to an integer ratio:
k : 1 = `(4/3)` : 1
∴ k = 4 : 3
Hence, the x-axis divides the segment joining (5, 4) and (1, −3) in the ratio 4 : 3.
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