Advertisements
Advertisements
प्रश्न
Find the perimeter and area of the figure given below. `(pi = 22/7)`
Advertisements
उत्तर
Length of the arc of the semicircle = `1/2 xx 2pi"r" "units"`
= `22/7 xx 7/2 "m"` = 11 m
∴ Perimeter = Sum of all lengths of sides that form the closed boundary
P = 11 + 10 + 7 + 10 m
Perimeter = 38 m
Area = Area of the rectangle – Area of semicircle
= `("l" xx "b") - 1/2 pi"r"^2 "sq.units"`
= `(10 xx 7) - 1/2 xx 22/7 xx 7/2 xx 7/2`
= `70 - (11 xx 7)/(2 xx 2)`
= `(280 - 77)/4`
= `203/4`
= 50.75 m2 (approx)
Area of the figure = 50.75 m2 (approx)
APPEARS IN
संबंधित प्रश्न
Find the area of the shaded part in the following figure. (π = 3.14)
Find the area of the shaded part in the following figure. (π = 3.14)
Find the area of the combined figure given, formed by joining a semicircle of diameter 6 cm with a triangle of base 6 cm and height 9 cm. (π = 3.14)
Find the perimeter and area of the following shape
A square of side 2 cm is joined with a rectangle of length 15 cm and breadth 10 cm. Find the perimeter of the combined shape
If two identical rectangles of perimeter 30 cm are joined together, then the perimeter of the new shape will be
A closed shape has 20 equal sides and one of its sides is 3 cm. Find its perimeter
A rectangle has length 40 cm and breadth 20 cm. How many squares with side 10 cm can be formed from it
Two plots have the same perimeter. One is a square of side 10 m and another is a rectangle of breadth 8 m. Which plot has the greater area and by how much?
Look at the picture of the house given and find the total area of the shaded portion.
