Question

Find the number of ways of selecting a team of 3 boys and 2 girls from 6 boys and 4 girls

Answer 1

There are 6 boys and 4 girls.

∴ the number of ways in which 3 boys and 2 girls can be selected

= ⁶C₃ × ⁴C₂

= `(6!)/(3!3!) xx (4!)/(2!2!)` 

= `(6 xx 5 xx 4)/(3 xx 2 xx 1) xx (4 xx 3)/(2 xx 1)`

= 20 × 6

= 120.