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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Find the number of 6-digit numbers using the digits 3, 4, 5, 6, 7, 8 without repetition. How many of these numbers are divisible by 5 - Mathematics and Statistics

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प्रश्न

Find the number of 6-digit numbers using the digits 3, 4, 5, 6, 7, 8 without repetition. How many of these numbers are divisible by 5

बेरीज
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उत्तर

There are 6 different digits and we have to form 6-digit numbers, i.e., n = 6, r = 6

If no digit is repeated, the total numbers with 6-digits can be formed = nPr

= 6P6

= 6!

= 6 x 5 x 4 x 3 x 2 x 1

= 720.

Since the number is divisible by 5, the unit's place of 6-digits number can be filled in only one way by the digit 5.

Remaining 5 positions can be filled from the remaining 5 digits in 5P5  ways.

Hence, the total number of 6-digit numbers divisible by 5 = 1 x 5P5 = 5!

= 5 x 4 x 3 x 2 x 1

= 120.

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Permutations - Permutations When Repetitions Are Allowed
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Permutations and Combination - Exercise 3.3 [पृष्ठ ५५]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 3 Permutations and Combination
Exercise 3.3 | Q 12. (a) | पृष्ठ ५५

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