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प्रश्न
Find the nature of the roots of the following quadratic equation:
`12x^2 - 4sqrt(15)x + 5 = 0`
बेरीज
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उत्तर
The given equation is `12x^2 - 4sqrt(15)x + 5 = 0`
This is of the form ax2 + bx + c = 0, where a = 12, b = `-4sqrt(15)` and c = 5
∴ Discriminant, D = b2 – 4ac
= `(-4sqrt(15))^2 - 4 xx 12 xx 5`
= 240 – 240
= 0
Hence, the given equation has real and equal roots.
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