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प्रश्न
Find the mode from the following:
| Mid-Value | 12 | 18 | 24 | 30 | 36 | 42 | 48 |
| Frequency | 20 | 12 | 8 | 24 | 16 | 8 | 12 |
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उत्तर
To find the mode from the given data, we first need to convert the mid-values into class intervals and then apply the formula for the mode of grouped data.
1. Find the class intervals
The difference between consecutive mid-values is constant: 18 – 12 = 6. So, the class width (h) is 6.
To find the lower and upper limits of each class, we subtract and add half of the width `(6/2 = 3)` to each mid-value.
| Class Interval | Mid-Value | Frequency (f) |
| 9 – 15 | 12 | 20 |
| 15 – 21 | 18 | 12 |
| 21 – 27 | 24 | 8 |
| 27 – 33 | 30 | 24 (Highest Frequency) |
| 33 – 39 | 36 | 16 |
| 39 – 45 | 42 | 8 |
| 45 – 51 | 48 | 12 |
2. Identify the modal class
The highest frequency is 24, which corresponds to the class interval 27 – 33.
Lower limit (L) of the modal class = 27
Frequency of modal class (f1) = 24
Frequency of preceding class (f0) = 8
Frequency of succeeding class (f2) = 16
Class width (h) = 6
3. Calculate the mode
We use the formula:
Mode = `L + ((f_1 - f_0)/(2f_1 - f_0 - f2)) xx h`
Substituting the values:
Mode = `27 + ((24 - 8)/(2(24) - 8 - 16)) xx 6`
Mode = `27 + (16/(48 - 24)) xx 6`
Mode = `27 + (16/24) xx 6`
Mode = `27 + (2/3) xx 6`
Mode = 27 + (2 × 2)
Mode = 27 + 4
Mode = 31
The mode of the given data is 31.
