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प्रश्न
Find the measure of angles A and B in the following, where A and B are acute.
sin (A+ B) = `sqrt3/2 and cos 2A = 1/2`
बेरीज
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उत्तर
Given:
sin (A + B) = `sqrt3/2`, cos 2A = `1/2`, ...[A, B Acute]
Step 1: Find A
Since A is acute → 0° < 2A < 180°
cos x = `1/2` in this range at x = 60°
2A = 60° = A = 30°
Step 2: use sin (A + B) = `sqrt3/2`
sin(A + B) = `sqrt3/2` = A + B = 60° or 120°
A = 30°
A + B = 60° = B = 30° acute
A + B = 120° = B = 90°, not acute
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