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प्रश्न
Find the mean by step deviation method:
| Class | 0 – 20 | 20 – 40 | 40 –60 | 60 – 80 | 80 – 100 | 100 – 120 |
| Frequency | 20 | 35 | 52 | 44 | 38 | 31 |
बेरीज
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उत्तर
Step 1: Prepare the data table
We will identify the class marks (xi) and calculate the step deviations (ui).
Class size (h): 20 (Since 20 – 0 = 20)
Assumed Mean (A): Let’s choose the middle class mark, 70.
| Class | Frequency (fi) |
Class Mark (xi) |
`bb(u_i = (x_i - 70)/20)` | fiui |
| 0 – 20 | 20 | 10 | –3 | –60 |
| 20 – 40 | 35 | 30 | –2 | –70 |
| 40 – 60 | 52 | 50 | –1 | –52 |
| 60 – 80 | 44 | 70 | 0 | 0 |
| 80 – 100 | 38 | 90 | 1 | 38 |
| 100 – 120 | 31 | 110 | 2 | 62 |
| Total | Σfi = 220 | Σfiui = –82 |
Step 2: Calculate the mean
Now, we substitute the values into the formula:
1. Sum of frequencies (Σfi): 220
2. Sum of fiui: –60 – 70 – 52 + 0 + 38 + 62 = –82
3. Calculation:
`barx = 70 + ((-82)/(220)) xx 20`
`barx = 70 + ((-82)/(11))`
`barx = 70 - 7.4545...`
`barx ≈ 62.55`
The mean of the given data is approximately 62.55.
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