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प्रश्न
Find the mean by direct method:
| Class interval | 0 – 8 | 8 – 16 | 16 – 24 | 24 – 32 | 32 – 40 |
| Frequency | 8 | 10 | 15 | 9 | 8 |
बेरीज
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उत्तर
Step 1: Calculate midpoints (xi) and product (fixi)
The midpoint xi is calculated as:
`x_i = ("Lower Limit" + "Upper Limit")/2`
| Class Interval | Frequency (fi) | Midpoint (xi) | fi × xi |
| 0 – 8 | 8 | 4 | 32 |
| 8 – 16 | 10 | 12 | 120 |
| 16 – 24 | 15 | 20 | 300 |
| 24 – 32 | 9 | 28 | 252 |
| 32 – 40 | 8 | 36 | 288 |
| Total | Σfi = 50 | Σfixi = 992 |
Step 2: Apply the mean formula
The formula for the mean `(barx)` using the direct method is:
`barx = (sumf_ix_i)/(sumf_i)`
Substituting the values from our table:
`barx = 992/50`
`barx = 19.84`
The mean for the given data is 19.84.
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