मराठी

Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = Product of the two numbers. 26 and 91

Advertisements
Advertisements

प्रश्न

Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = Product of the two numbers.

26 and 91

बेरीज
Advertisements

उत्तर

26 = 2 × 13

91 = 7 × 13 

L.C.M of 26 and 91 = 2 × 7 × 13

L.C.M of 26 and 91 = 182

H.C.F of 26 and 91 = 13

We know that,

Now, LCM × HCF = First number × Second number

⇒ 182 × 13 = 26 × 91

⇒ 2366 = 2366

i.e., LCM × HCF = Product of two numbers.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Real Numbers - EXERCISE 1.1 [पृष्ठ ५]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
पाठ 1 Real Numbers
EXERCISE 1.1 | Q 2. (i) | पृष्ठ ५

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Express the number as a product of its prime factor:

140


Given that HCF (306, 657) = 9, find LCM (306, 657).


Determine the prime factorisation of the following positive integer:

 20570


Find the LCM and HCF of the following integers by applying the prime factorisation method:

 24, 15 and 36


The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, find the other.


If the product of two numbers is 1080 and their HCF is 30, find their LCM.


Express the number as a product of its prime factor:

3825


If p1x1 × p2x2 × p3x3 × p4x4 = 113400 where p1, p2, p3, p4 are primes in ascending order and x1, x2, x3, x4, are integers, find the value of p1, p2, p3, p4 and x1, x2, x3, x4


Find the L.C.M. and H.C.F. of 408 and 170 by applying the fundamental theorem of Arithmetic


Express 98 as a product of its primes.


If two positive integers A and B can be expressed as A = xy3 and B = x4y2z; x, y being prime numbers then HCF (A, B) is ______.


When a number is divided by 7, its remainder is always ______.


Find the HCF and LCM of 26, 65 and 117, using prime factorisation.


The LCM of smallest 2-digit number and smallest composite number is ______.


Two numbers are in the ratio 2 : 3 and their LCM is 180. What is the HCF of these numbers?


Assertion (A): The HCF of two numbers is 5 and their product is 150. Then their LCM is 40.

Reason(R): For any two positive integers a and b, HCF (a, b) × LCM (a, b) = a × b.


If HCF (72, 120) = 24, then LCM (72, 120) is ______.


The mean of first ten natural numbers is ______.


The prime factorisation of the number 5488 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×