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प्रश्न
Find the G.P. whose 2nd and 5th terms are `-3/2 "and" 81/16` respectively.
बेरीज
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उत्तर
`T_2 = ar^(2 - 1)`
ar = `-3/2` ...(1)
`T_5 = ar^(5 - 1)`
ar4 = `81/16` ...(2)
Divide Equation 2 by Equation 1 to eliminate a:
`(ar^4)/(ar) = (81/16)/(-3/2)`
`r^3 = 81/16 xx (-2/3)`
`r^3 = -27/8`
Taking the cube root of both sides:
r = `root3(-27/8)`
r = `-3/2`
Substitute the value of r = `-3/2` back into Equation 1:
`a xx (-3/2)`
= `-3/2`
a = 1
T1 ⇒ a = 1
T2 ⇒ ar = `1 xx (-3/2)`
= `-3/2`
T3 ⇒ `ar^2 = 1 xx (-3/2)^2`
= `9/4`
T4 ⇒ `ar^3 = 1 xx (-3/2)^3`
= `-27/8`
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