Advertisements
Advertisements
प्रश्न
Find the fourth proportional to:
x3 - y2, x4 + x2y2 + y4, x - y.
Advertisements
उत्तर
Let A be the fourth proportional then
x3 - y2 : x4 + x2y2 + y4 = x - y : A
⇒ `(x^3 - y^3)/(x^4 + x^2y^2 + y^4) = (x - y)/"A"`
⇒ A(x3 - y3) = (x - y)(x4 + x2y2 + y4)
⇒ A = `((x - y)(x^4 + x^2y^2 + y^4))/(x^3 - y^3)`
⇒ A = `((x - y)(x^2 + y^2 + xy)(x^2 + y^2 - xy))/((x - y)(x^2 + xy + y^2)`
⇒ A = x2 + y2 - xy.
APPEARS IN
संबंधित प्रश्न
Find the fourth proportional to 1.5, 4.5 and 3.5
Find mean proportional of `( x + y)/( x - y), (x^2 - y^2)/(x^2y^2)`
Find the mean proportion of the following :
0.09 and 0.25
What least number must be added to each of the numbers 5, 11, 19 and 37, so that they are in proportion?
Find the fourth proportional to `(1)/(3), (1)/(4), (1)/(5)`
Find the third proportional to Rs. 3, Rs. 12
Find the value of x if 5 : 3 : : x : 6.
Find the missing number in the box in the proportions:
`3/8 = square/20`
There is a number in the box `square` such that `square`, 24, 9, 12 are in proportion. The number in the box is ______.
A recipe calls for 1 cup of milk for every `2 1/2` cups of flour to make a cake that would feed 6 persons. How many cups of both flour and milk will be needed to make a similar cake for 8 people?
