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Find the equation of the parabola with vertex at the origin, axis along X-axis and passing through the point (3, 4) - Mathematics and Statistics

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प्रश्न

Find the equation of the parabola with vertex at the origin, axis along X-axis and passing through the point (3, 4)

बेरीज
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उत्तर

Vertex of the parabola is at the origin (0, 0) and its axis is along X-axis.

∴ Equation of the parabola can be either

y2 = 4ax or y2 = – 4ax

Since the parabola passes through (3, 4), it lies in 1st quadrant.

∴ Required parabola is y2 = 4ax.

Substituting x = 3 and y = 4 in y2 = 4ax, we get

(4)2 = 4a(3)

∴ a = `16/12 = 4/3`

∴ The required equation of the parabola is

y2 = `4(4/3)`x, i.e., y2 = `(16/3)`x, i.e., 3y2 = 16x.

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Conic Sections - Parabola
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Conic Sections - Exercise 7.1 [पृष्ठ १४९]

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