Question

Find the equation of the line whose slope is `-4/3` and which passes through (−3, 4).

Answer 1

Given, slope = `-4/3`

The equation passes through (−3, 4) = (x₁, y₁)

Substituting the values in y – y₁ = m (x − x₁), we get,

`y - 4 = -4/3(x + 3)`

3y – 12 = −4x – 12

4x + 3y = 0, which is the required equation.