Question

Find the equation of the line passing through (5, –3) and parallel to x – 3y = 4.

Answer 1

x − 3y = 4

`=>` 3y = x – 4

`=> y = 1/3x - 4/3`

Slope of this line =`1/3`

Slope of a line parallel to this line = `1/3`

Required equation of the line passing through (5, −3) is

y − y₁ = m(x − x₁)

`y - (-3) = 1/3 (x - 5)`

`y + 3 = 1/3 (x -5)`

3y + 9 = x – 5

3y = x – 5 – 9

3y = x – 14

x − 3y − 14 = 0