Question

Find the equation of the line parallel to the line 3x + 2y = 8 and passing through the point (0, 1).

Answer 1

3x + 2y = 8

2y = −3x + 8

`y = -3/2x + 8/2` 

Slope of given line = `-3/2`

Since the required line is parallel to given straight line.

∴ Slope of required line (m) = `-3/2`

Now the equation of the required line is given by:

y – y₁ = m(x – x₁)

`=> y - 1 = -3/2 (x - 0)`

`=>` 2y – 2 = −3x

`=>` 3x + 2y = 2