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प्रश्न
Find the equation of the line having slope `1/2` and containing the point (3, −2).
बेरीज
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उत्तर
Given, slope(m) = `1/2` and the line passes through (3, −2).
Equation of the line in slope point form is y − y1 = m(x − x1)
∴ The equation of the required line is
[y − (− 2)] = `1/2("x" - 3)`
∴ 2(y + 2) = x − 3
∴ 2y + 4 = x − 3
∴ x − 2y − 7 = 0
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