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Find the equation of the hyperbola with vertices (0, ± 7), e = 43 - Mathematics

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प्रश्न

Find the equation of the hyperbola with vertices (0, ± 7), e = `4/3`

बेरीज
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उत्तर

Given that vertices (0, ± 7), e = `4/3`

Clearly, the hyperbola is vertical.

Vertices = (± 0, a)

∴ a = 7 and e = `4/3`

We know that b2 = a2(e2 – 1)

⇒ b2 = `49(16/9 - 1)`

⇒ b2 = `49 xx 7/9`

⇒ b2 = `343/9`

Hence, the equation of the hyperbola is `y^2/49 - (9x^2)/343` = 1

⇒ 9x2 – 7y2 + 343 = 0

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पाठ 11: Conic Sections - Exercise [पृष्ठ २०४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 11 Conic Sections
Exercise | Q 32.(b) | पृष्ठ २०४

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