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Find the equation of tangent and normal to the curve given by x – 7 cos t andy = 2 sin t, t ∈ R at any point on the curve - Mathematics

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प्रश्न

Find the equation of tangent and normal to the curve given by x – 7 cos t andy = 2 sin t, t ∈ R at any point on the curve

बेरीज
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उत्तर

x = 7 cos t and y = 2 sin t, t ∈ R

Differentiating w.r.t. ‘t’,

`("d"x)/"dt"` = – 7 sin t and `("d"y)/"dt"` = 2 cos t

Slope of the tangent ‘m’

`("d"y)/("d"x) = (("d"y)/("dt"))/(("d"x)/("d"t"))`

= `(2 cot"t")/(- 7 sin "t")`

Any point on the curve is (7 Cos t, 2 sin t)

Equation of tangent is y – y1 = m (x – x1)

y – 2 sint = `- (2cot"t")/(7sin"t")` (x – 7 cos t)

7y sin t – 14 sin2t = – 2x cos t + 14 cos2t

2x cos t + 7 y sin t – 14(sin2t + cos2t) = 0

2x cos t + 7y sin t – 14 = 0

Now slope of normal is `- 1/3 = (7sin"t")/(2cos"t")`

Equation of normal is y – y1 = `- 1/"m"` (x – x1)

y – 2 sin t = `(7sin"t")/(2cos"t")` (x – 7 cos t)

2y cos t – 4 sin t cos t = 7x sin t – 49 sin t cos t 7x sin t – 2y cos t – 45 sin t cos t = 0

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पाठ 7: Applications of Differential Calculus - Exercise 7.2 [पृष्ठ १५]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 7 Applications of Differential Calculus
Exercise 7.2 | Q 8 | पृष्ठ १५

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