Advertisements
Advertisements
प्रश्न
Find the distance between the following pair of points:
`(sqrt(3)+1,1)` and `(0, sqrt(3))`
Advertisements
उत्तर
Step 1: Formula
The distance between two points (x1, y1) and (x2, y2) is given by:
`d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)`
Step 2: Substitute values
`x_1 = sqrt3 + 1, y_1 = 1, x_2 = 0, y_2 = sqrt3`
`d = sqrt((0 - (sqrt3 + 1))^2 + (sqrt3 - 1)^2)`
Step 3: Simplify
`d = sqrt((sqrt3 + 1)^2 + (sqrt3 - 1)^2)`
`= sqrt((3 + 2sqrt3 + 1) + (3 - 2sqrt3 + 1))`
`= sqrt((4 + 2sqrt3) + (4 - 2sqrt3))`
`= sqrt8`
Step 4: Simplify further
`d = 2sqrt2`
APPEARS IN
संबंधित प्रश्न
If A(5, 2), B(2, −2) and C(−2, t) are the vertices of a right angled triangle with ∠B = 90°, then find the value of t.
Find the value of x, if the distance between the points (x, – 1) and (3, 2) is 5.
If two vertices of an equilateral triangle be (0, 0), (3, √3 ), find the third vertex
Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.
Find the distance between the points
P(a sin ∝,a cos ∝ )and Q( acos ∝ ,- asin ∝)
Find the point on the x-axis equidistant from the points (5,4) and (-2,3).
Find the point on y-axis whose distances from the points A (6, 7) and B (4, -3) are in the ratio 1: 2.
If the distance between point L(x, 7) and point M(1, 15) is 10, then find the value of x
Point P(0, 2) is the point of intersection of y-axis and perpendicular bisector of line segment joining the points A(–1, 1) and B(3, 3).
What is the distance of the point (– 5, 4) from the origin?
