Question

Find the discriminant of the quadratic equation \[3\sqrt{3}x^2 + 10x + \sqrt{3} = 0\].

Answer 1

Given that quadric equation is \[3\sqrt{3} x^2 + 10x + \sqrt{3} = 0\].

Then, find the value of discriminant.

Here, `a = 3sqrt3, b = 10 and c = sqrt3` 

As we know that discrimenant `D = b^2 - 4ac`

Putting the value of `a = 3sqrt3, b = 10 and c = sqrt 3` 

`= (10)^2 - 4 xx 3 sqrt3 xx sqrt3`

= 100 - 36

= 64

Thus, the value of discriminant is D = 64.