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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान इयत्ता ११

Find the derivatives of the following functions using first principle. f(x) = – x2 + 2

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प्रश्न

Find the derivatives of the following functions using first principle.

f(x) = – x2 + 2

बेरीज
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उत्तर

f(x + Δx) = – (x + Δx)2 + 2

f(x + Δx) – f(x) = – [x2 + 2x Δx + (Δx)2] + 2 – [– x2 + 2]

`(f(x + Deltax) - f(x))/(Deltax) = (- x^2 + 2xDeltax - (Deltax)^2 + 2 + x^2 - 2)/(Deltax)`

`(f(x + Deltax) - f(x))/(Deltax) = (- 2xDeltax - (Deltax)^2)/(Deltax)`

`(f(x + Deltax) - f(x))/(Deltax) = (-2xDeltax)/(Deltax) - (Deltax)^2/(Deltax)`

`(f(x + Deltax) - f(x))/(Deltax) = - 2x - Deltax`

`lim_(Deltax -> 0) (f(x + Deltax) - f(x))/(Deltax) = lim_(Deltax -> 0) (- 2x) - lim_(Deltax -> 0) Deltax`

`f"'"(x) = - 2x - 0`

`f"'"(x) = - 2x`

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पाठ 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.1 [पृष्ठ १४७]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.1 | Q 1. (iii) | पृष्ठ १४७
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