Question

Find the de-Broglie Wavelength for an electron moving at the speed of 5.0 × 10⁶ m/s. (mass of electron is 9.1 × 10^-31)

पर्याय

• 1 × 10^-10 m

• 2 × 10^-10 m

• 3 × 10^-10 m

• 4 × 10^-10 m

Answer 1

1 × 10^-10 m

Explanation:

`lambda = h/p = h/(mV)`

= `(6.63 xx 10^-34 J.S)/((9.1 xx 10^-31  kg)(5.0 xx 10^6  m/s))`

= 1 × 10^-10 m