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प्रश्न
Find the co-ordinates of a point R which divides the line segment joining the points P(−2, 3) and Q(4, 7) internally in the ratio 4:7.
बेरीज
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उत्तर
Formula (section / internal division):
If R divides PQ internally in the ratio m1:m2,
So PR : RQ = m1:m2,
Then x = `(m1 xx x2 + m2 xx x1) / (m1 + m2)`,
`y = (m1 xx y2 + m2 xx y1) / (m1 + m2)`
Identify values:
- P(x1, y1) = (−2, 3)
- Q(x2, y2) = (4, 7)
- Ratio PR : RQ = 4:7,
so m1 = 4, m2 = 7
Substitute into the formula:
x = `((4 xx x2) + (7 xx x1)) / (4 + 7)`
= `(4 xx 4 + 7 xx (−2)) / 11`
= `(16 − 14) / 11`
∴ x = `2/11`
y = `((4 xx y2) + (7 xx y1)) / (4 + 7)`
= `(4 xx 7 + 7 xx 3) / 11`
= `(28 + 21) / 11`
∴ y = `49/11`
Hence, the co-ordinates of a point R that divides the line segment joining the points are `(2/11, 49/11)`
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पाठ 11: Section formula - Exercise 11A [पृष्ठ २२८]
