Advertisements
Advertisements
प्रश्न
Find the circumference of the circle whose area is 25times the area of the circle with radius 7cm.
Advertisements
उत्तर
The Area of a Circle with radius r = πr2
The Area of a Circle with radius7 = π(7)2
The Area of the bigger Circle
= 25 x π(7)2
= π(72 x 52)
= π(352)
Let radius of the bigger Circle = R
R2 = π(352)
⇒ radius of the bigger Circle = 35
The Circumference of a Circle with radius r = 2πr
The Circumference of a Circle with radiu 35r
= 2π x 35
= 220cm.
APPEARS IN
संबंधित प्रश्न
In Fig. 4, ABCD is a square of side 14 cm. Semi-circles are drawn with each side of square as diameter. Find the area of the shaded region.
(use `pi=22/7`)
In Fig. 7, are shown two arcs PAQ and PBQ. Arc PAQ is a part of circle with centre O and radius OP while arc PBQ is a semi-circle drawn on PQ ad diameter with centre M. If OP = PQ = 10 cm show that area of shaded region is `25(sqrt3-pi/6)cm^2`.
In circle of radius 6cm, chord of length 10 cm makes an angle of 110° at the centre of circle find Circumference of the circle
The hypotenuse of a right-angled triangle is 65 cm and its base is 60 cm. Find the length of perpendicular and the area of the triangle.
Find the curved surface area , the total surface area and the volume of a cone if its :
Height = 16 cm , diameter = 24 cm
The radii of two circles are 25 cm and 18 cm. Find the radius of the circle which has a circumference equal to the sum of circumferences of these two circles.
In the given figure, the area of the shaded portion is 770 cm2. If the circumference of the outer circle is 132 cm, find the width of the shaded portion.
The radius of a circle is 5 m. Find the circumference of the circle whose area is 49 times the area of the given circle.
Find the area and perimeter of the circles with following: Diameter = 35cm
A bucket is raised from a well by means of a rope wound round a wheel of diameter 35 cm. If the bucket ascends in 2 minutes with a uniform speed of 1.1 m per sec, calculate the number of complete revolutions the wheel makes in raising the bucket.
