Question

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60° [Use `pi = 22/7`]

Answer 1

Let OACB be a sector of the circle making 60° angle at centre O of the circle.

Area of sector of angle θ  = `theta/360^@xxpir^2`

Area of sector OACB = `60^@/360^@xx22/7xx(6)^2`

`=1/6xx22/7xx6xx6= 132/7 cm^2`

Therefore, the area of the sector of the circle making 60° at the centre of the circle is 132/7 cm²