मराठी

Find the area of a quadrilateral plot of ground whose diagonals are 140 m and 130 m and intersect each other at right angles. Find also the cost of the land at ₹ 10 per m^2. - Mathematics

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प्रश्न

Find the area of a quadrilateral plot of ground whose diagonals are 140 m and 130 m and intersect each other at right angles. Find also the cost of the land at ₹ 10 per m2.

बेरीज
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उत्तर

Given:

Diagonals = 140 m and 130 m and they intersect at right angles.

Cost = ₹ 10 per m2.

Step-wise calculation:

1. Formula: When the diagonals of a quadrilateral are perpendicular.

Area = `1/2` × product of the diagonals

2. Area = `1/2 xx 140 xx 130`

= 70 × 130

= 9,100 m2

3. Cost = Area × Rate

= 9,100 × ₹ 10

= ₹ 91,000

Area of the plot = 9,100 m2.

Cost of the land at ₹ 10 per m2 = ₹ 91,000.

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पाठ 16: Mensuration - Exercise 16B [पृष्ठ ३२४]

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नूतन Mathematics [English] Class 9 ICSE
पाठ 16 Mensuration
Exercise 16B | Q 3. | पृष्ठ ३२४
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