Advertisements
Advertisements
प्रश्न
Find the area of a body which experiences a pressure of 50000 Pa by a thrust of 100 N?
Advertisements
उत्तर
Pressure on the body = 50,000 pa
Force or thrust = 100 N
By substituting the values we get,
a = `100/(50,000)`
= `10/5000`
A = `10/5000`
= `10/(5 xx 10^3)`
= `2/10^3`
= 2 × 10−3 m2
APPEARS IN
संबंधित प्रश्न
In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)
The unit of thrust is ..........
How is the thrust related to pressure?
The figure shows a brick of weight 2 kgf and dimensions 20 cm × 10 cm × 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case.
A beaker containing a liquid is kept inside a big closed jar. If the air inside the jar is continuously pumped out, the pressure in the liquid near the bottom of the liquid will
Consider the situation of the previous problem. Let the water push the left wall by a force F1 and the right wall by a force F2.
In a hydraulic lift, the input piston had surface area 30 cm2 and the output piston has surface area of 1500 cm2. If a force of 25 N is applied to the input piston, calculate weight/force on output piston.
If the same force is made to act on a larger area, the pressure ______.
Pressure is directly proportional to the area of contact.
Assertion: The pressure at the bottom of the sea is lesser than that near the surface.
Reason: The pressure exerted by a liquid depends upon the depth of the liquid and density of the liquid.
