मराठी

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length ((5π)/3) cm.

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प्रश्न

Find the angle subtended at the centre of a circle of radius 5 cm by an arc of length `((5π)/3)`cm.

बेरीज
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उत्तर

Radius (r) = 5 cm

𝜃 = angle subtended at centre (degrees)

Length of Arc =`theta/360^@`× 2𝜋r cm

But arc length =`5pi/3`𝑐𝑚

`theta/360^@× 2pi × 5 =(5pi)/3`

`theta=(360^@×pi)/(3×2pi)= 60^@`

∴ Angle subtended at centre = 60°

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पाठ 13: Areas Related to Circles - EXERCISE 13.2 [पृष्ठ १३.२०]

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आर.डी. शर्मा Mathematics [English] Class 10
पाठ 13 Areas Related to Circles
EXERCISE 13.2 | Q 2. | पृष्ठ १३.२०
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